Using Java 8 Streams to Find the Second-Highest Salary in an Employee List

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To find the second-highest salary from a list of employees using Java 8 streams, you can follow these steps:

1. Create a list of employees with their salaries.
2. Use Java 8 streams to sort the employees by salary in descending order.
3. Skip the first element (which is the employee with the highest salary).
4. Get the first element of the remaining stream (which is the employee with the second-highest salary).

Example code:

java
import java.util.ArrayList;
import java.util.List;

class Employee {
    private String name;
    private double salary;

    public Employee(String name, double salary) {
        this.name = name;
        this.salary = salary;
    }

    public double getSalary() {
        return salary;
    }
}

public class SecondHighestSalary {
    public static void main(String[] args) {
        List<Employee> employees = new ArrayList<>();
        employees.add(new Employee("John", 60000.0));
        employees.add(new Employee("Jane", 75000.0));
        employees.add(new Employee("Bob", 55000.0));
        employees.add(new Employee("Alice", 80000.0));

        // Use Java 8 streams to find the second-highest salary
        double secondHighestSalary = employees.stream()
            .sorted((e1, e2) -> Double.compare(e2.getSalary(), e1.getSalary()))
            .skip(1)
            .findFirst()
            .map(Employee::getSalary)
            .orElse(0.0);

        System.out.println("Second-highest salary: " + secondHighestSalary);
    }
}

Sample Output:

output
Second-highest salary: 75000.0

In this code, we create a list of employees, sort them by salary in descending order, skip the first element (which has the highest salary), and then retrieve the second element using findFirst. Finally, we extract the salary from the employee and print the second-highest salary, which is 75000.0 in this example.